Who's in the Middle

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Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 11549    Accepted Submission(s): 5481

5
2
4
1
3
5

3

Hint
 
INPUT DETAILS: 

Five cows with milk outputs of 1..5 

OUTPUT DETAILS: 

1 and 2 are below 3; 4 and 5 are above 3.
 

#include<stdio.h>
#include<algorithm>
using namespace std;
int x[100000];
int main()
{
 int n,i;
 while(scanf("%d",&n)!=EOF)
 {
  for(i=0;i<n;i++)
  scanf("%d",&x[i]);
  sort(x,x+n);
  printf("%d\n",x[n/2]);
 }
 return 0;
}

Who's in the Middle

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原文地址：http://blog.csdn.net/l15738519366/article/details/47749241