Time Limit: 5000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 1791 Accepted Submission(s): 696
#include<stdio.h>
#include<string.h>
#define INF 0x3f3f3f3f
int vis[110],map[110][110],dis[110];
int n,m;
void init(){
int i,j;
for(i=0;i<n;i++)
for(j=0;j<n;j++){
if(j==i)
map[i][j]=map[j][i]=0;
else
map[i][j]=map[j][i]=INF;
}
}
void dijkstra(int beg){
int i;
memset(vis,0,sizeof(vis));
for(i=0;i<n;i++)
dis[i]=map[beg][i];
for(i=0;i<n;i++){
int j,k,temp=INF;
for(j=0;j<n;j++)
if(!vis[j]&&temp>dis[j])
temp=dis[k=j];
if(temp==INF)
break;
vis[k]=1;
for(j=0;j<n;j++)
if(!vis[j]&&dis[j]>dis[k]+map[k][j])
dis[j]=dis[k]+map[k][j];
}
}
int main(){
while(scanf("%d%d",&n,&m)!=EOF){
init();
for(int i=0;i<m;i++){
int a,b;
scanf("%d%d",&a,&b);
map[a][b]=map[b][a]=1;
}
int i,j,max=-1;
for(i=0;i<n;i++){
dijkstra(i);
for(j=i;j<n;j++){
if(max<dis[j])
max=dis[j];
}
}
if(max>7)
printf("No\n");
else
printf("Yes\n");
}
return 0;
} 版权声明:本文为博主原创文章,未经博主允许不得转载。
原文地址:http://blog.csdn.net/gui951753/article/details/47759253