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树的子结构

时间:2015-08-19 00:40:04      阅读:111      评论:0      收藏:0      [点我收藏+]

标签:二叉树

题目
输入两颗二叉树A和B,判断B是不是A的子结构.二叉树结点的定义如下:

先在A中找B的跟节点,若找到相同的,在判断左右子树是否相同.

struct BinaryTreeNode
{
    int     m_nValue;
    BinaryTreeNode* m_pLeft;
    BinaryTreeNode* m_pRight;
    BinaryTreeNode(int n) : m_nValue(n), m_pLeft(NULL), m_pRight(NULL) {};
};
bool HasSubtree(BinaryTreeNode* pRoot1, BinaryTreeNode* pRoot2);
bool DoesTree1HaveTree2(BinaryTreeNode* pRoot1, BinaryTreeNode* pRoot2);
bool HasSubtree(BinaryTreeNode* pRoot1, BinaryTreeNode* pRoot2)
{
    bool result = false;
    if (pRoot1 != NULL && pRoot2 != NULL)
    {
        if (pRoot1->m_nValue == pRoot2->m_nValue)
            result = DoesTree1HaveTree2(pRoot1, pRoot2);
        if (!result)
            result = HasSubtree(pRoot1->m_pLeft, pRoot2);
        if (!result)
            result = HasSubtree(pRoot1->m_pRight, pRoot2);

    }

    return result;
}

bool DoesTree1HaveTree2(BinaryTreeNode* pRoot1, BinaryTreeNode* pRoot2)
{   
    if (pRoot2 == NULL)
        return true;
    if (pRoot1 == NULL)
        return false;
    if (pRoot1->m_nValue != pRoot2->m_nValue)
        return false;
    return DoesTree1HaveTree2(pRoot1->m_pLeft, pRoot2->m_pLeft) &&
           DoesTree1HaveTree2(pRoot1->m_pRight, pRoot2->m_pRight);
}

版权声明:本文为博主原创文章,未经博主允许不得转载。

树的子结构

标签:二叉树

原文地址:http://blog.csdn.net/nizhannizhan/article/details/47762879

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