Given two binary strings, return their sum (also a binary string).
For example,
a = "11"
b = "1"
Return "100".
public class Solution {
public String addBinary(String a, String b) {
int alen=a.length();
int blen=b.length();
int len=alen>blen?(alen+1):(blen+1);
StringBuffer sba=new StringBuffer(a).reverse();
StringBuffer sbb=new StringBuffer(b).reverse();
while(sba.length()<len) sba.append("0");
while(sbb.length()<len) sbb.append("0");
StringBuffer sb=new StringBuffer("");
int tmp = 0;
for(int i=0;i<len;i++){
int ia=(int) (sba.charAt(i)-'0');
int ib=(int) (sbb.charAt(i)-'0');
int ic=ia+ib+tmp;
tmp=0;
if(ic==3){
sb.append("1");
tmp=1;
}
else if( ic==2){
sb.append("0");
tmp=1;
}
else{
new String();
sb.append(String.valueOf(ic));
tmp=0;
}
}
// if last is 0 ; then delete
if(sb.charAt(sb.length()-1)=='0')
sb.deleteCharAt(sb.length()-1);
return sb.reverse().toString();
}
}原文地址:http://blog.csdn.net/dutsoft/article/details/37699951