标签:
已知两个非降序链表序列S1与S2,设计函数构造出S1与S2的交集新链表S3。
输入格式说明:
输入分2行,分别在每行给出由若干个正整数构成的非降序序列,用-1表示序列的结尾(-1不属于这个序列)。数字用空格间隔。
输出格式说明:
在一行中输出两个输入序列的交集序列,数字间用空格分开,结尾不能有多余空格;若新链表为空,输出“NULL”。
样例输入与输出:
序号 | 输入 | 输出 |
1 |
1 2 5 -1 2 4 5 8 10 -1 |
2 5 |
2 |
1 3 5 -1 2 4 6 8 10 -1 |
NULL |
3 |
1 2 3 4 5 -1 1 2 3 4 5 -1 |
1 2 3 4 5 |
4 |
3 5 7 -1 2 3 4 5 6 7 8 -1 |
3 5 7 |
5 |
-1 10 100 1000 -1 |
NULL |
#include<stdio.h> #include<stdlib.h> #include <malloc.h> typedef struct Node { int dex; //int cof; struct Node * Next; }node; int main() { //Qlink newLink; //newLink=(Link*)malloc(sizeof(Link)); struct Node *head,*tail; head=(node*)malloc(sizeof(node)); tail=(node*)malloc(sizeof(node)); tail->Next=NULL; head->Next=tail; struct Node *pthis,*pthat; pthis=head;pthat=pthis; //第一个链表 int dex; while(scanf("%d",&dex)){ pthis=(node*)malloc(sizeof(node)); pthis->dex=dex; pthis->Next=pthat->Next; pthat->Next=pthis; pthat=pthis; if(dex==-1)break; } //第二个链表 struct Node *head1,*tail1; head1=(node*)malloc(sizeof(node)); tail1=(node*)malloc(sizeof(node)); tail1->Next=NULL; head1->Next=tail1; pthis=head1;pthat=pthis; getchar(); while(scanf("%d",&dex)){ pthis=(node*)malloc(sizeof(node)); pthis->dex=dex; pthis->Next=pthat->Next; pthat->Next=pthis; pthat=pthis; if(dex==-1)break; } //遍历 pthat=head->Next; pthis=head1->Next; //交集链表 struct Node *head2,*tail2; head2=(node*)malloc(sizeof(node)); tail2=(node*)malloc(sizeof(node)); struct Node *newNode,*pnew; tail2->Next=NULL; head2->Next=tail2; newNode=head2;pnew=newNode; if(pthat->dex==-1||pthis->dex==-1)//存在空链表 printf("NULL\n"); else { while(pthis->dex!=-1&&pthat->dex!=-1) { if(pthis->dex==pthat->dex)//比较每一位 { newNode=(node*)malloc(sizeof(node)); newNode->dex=pthat->dex; newNode->Next=pnew->Next; pnew->Next=newNode; pnew=newNode; pthis=pthis->Next; pthat=pthat->Next; } else if(pthis->dex<pthat->dex)pthis=pthis->Next; else pthat=pthat->Next; } pthat=head2->Next; if(pthat->Next==NULL)printf("NULL\n"); else{ while(pthat->Next!=NULL) { printf("%d",pthat->dex); if(pthat->Next->Next==NULL)printf("\n"); else printf(" "); pthat=pthat->Next; } } } //free(pthat); free(pthis);free(head);free(tail);free(head1); free(tail1);free(head2);free(tail2); free(newNode); return 0; }
Programming Ability Test学习 2-12. 两个有序链表序列的交集(20)
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原文地址:http://www.cnblogs.com/a842297171/p/4745629.html