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搜索关键字:arbitrage    ( 88个结果
POJ:Arbitrage (搜索,汇率换算是否赚?)
POJ 2240 http://poj.org/problem?id=2240 题意:判断是否存在使得汇率增多的环 【任意一个点的汇率增多都可以】 Floyd 简单变形 $w[i][j] = max(w[i][j], w[i][k] w[k][j])$ bellman_ford 判断正环 ...
分类:其他好文   时间:2020-05-19 18:09:56    阅读次数:55
Arbitrage POJ - 2240
#include<iostream> #include<queue> #include<cstdio> #include<cstring> using namespace std; double d[35]; int h[1010],cnt,n,pre[35]; bool vis[35]; stru ...
分类:其他好文   时间:2020-01-29 12:24:11    阅读次数:42
[kuangbin带你飞]专题四 最短路练习 I - Arbitrage(判断负环)
I - Arbitrage 题目链接:https://vjudge.net/contest/66569#problem/I 题目: Arbitrage is the use of discrepancies in currency exchange rates to transform one un ...
分类:其他好文   时间:2019-07-20 23:32:38    阅读次数:99
用SPFA 解决POJ2240
Arbitrage Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 30790 Accepted: 12761 Description Arbitrage is the use of discrepancies in curren ...
分类:其他好文   时间:2019-07-19 20:55:15    阅读次数:101
POJ2240:Arbitrage(最长路+正环)
Arbitrage 题目链接:http://poj.org/problem?id=2240 Description: Arbitrage is the use of discrepancies in currency exchange rates to transform one unit of a ...
分类:其他好文   时间:2019-02-04 20:56:05    阅读次数:192
PKU 百练OJ Arbitrage
可以参考这篇文章和这个题解 https://www.cnblogs.com/wangyuliang/p/9216365.html https://www.luogu.org/problemnew/solution/SP9340 ...
分类:其他好文   时间:2019-01-09 21:45:00    阅读次数:312
HDU 1217 Arbitrage(最短路径,Floyd算法)
Problem Description Arbitrage is the use of discrepancies in currency exchange rates to transform one unit of a currency into more than one unit of th ...
分类:编程语言   时间:2018-12-31 17:27:58    阅读次数:143
POJ 2240 Arbitrage
http://poj.org/problem?id=2240 Description Arbitrage is the use of discrepancies in currency exchange rates to transform one unit of a currency into m ...
分类:其他好文   时间:2018-10-16 19:21:50    阅读次数:92
最短路(Floyed、Dijkstra、Bellman-Ford、SPFA)
一、Floyed-Warshall算法 枚举中间点起点终点,对整个图进行松弛操作,就能得到整个图的多源最短路径; 例:POJ2240 Arbitrage Arbitrage is the use of discrepancies in currency exchange rates to trans ...
分类:其他好文   时间:2018-09-18 14:57:36    阅读次数:184
floyd
floyd可用于解决某些可传递性问题(如1<2,2<3,则1<3 ) POJ2240:http://poj.org/problem?id=2240 Arbitrage Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 28138 A ...
分类:其他好文   时间:2018-09-11 21:08:20    阅读次数:141
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