转:http://blog.csdn.net/doc_sgl/article/details/17103427这道题思想很简单··············分析:任意一条直线都可以表述为y = ax + b假设,有两个点(x1,y1), (x2,y2),如果他们都在这条直线上则有y1 = kx1 +b...
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其他好文 时间:
2015-06-15 15:54:30
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109
请允许我吐槽这个yiistrap,这个问题经常遇到,今天终于解决了。<?php$this->widget(‘\TbListView‘,array( ‘dataProvider‘=>$dataProvider, ‘itemView‘=>‘_view‘,));?>类似这种的。YiiStrap是你的main.php里配的别名。改成YiiStrap.widgets.TbListView哦我操,..
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其他好文 时间:
2015-06-15 00:27:24
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116
From a practical point to most people, <? extends Object> is the same as <?>, like everyone have suggested here. However, they differ in two very minor and subtle points: The JVMS (Java Virtual Mac...
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其他好文 时间:
2015-06-12 17:36:23
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228
Well, a medium problem. Use two pointers. One points to the curren number and the other points to the last unique number. Once duplicates occur, move ...
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其他好文 时间:
2015-06-09 23:22:45
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122
Triangular Sums时间限制:3000ms | 内存限制:65535KB难度:2描述ThenthTriangularnumber,T(n) = 1 + … +n, is the sum of the firstnintegers. It is the number of points in...
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其他好文 时间:
2015-06-08 00:55:50
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184
Not hard, but with some amount of coding. Brutal-force would work: iterate each unique pair of points. And I used "y=ax+b" to check each point which s...
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其他好文 时间:
2015-06-05 06:21:50
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176
Given n points on a 2D plane, find the maximum number of points that lie on the same straight line.解题思路:本题主要需要考虑到斜线的情况,可以分别计算出过points[i]直线最多含几个点,然后算出最...
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编程语言 时间:
2015-06-05 00:34:41
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138
cvFindExtrinsicCameraParams2函数的定义:1 void cvFindExtrinsicCameraParams2( const CvMat* object_points,2 const CvMat* im...
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其他好文 时间:
2015-05-31 16:39:23
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734
DescriptionGiven an integer N, your task is to judge whether there exist N points in the plane such that satisfy the following conditions:1. The dista...
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其他好文 时间:
2015-05-30 22:28:15
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121