-module(exe5_2).
-export([start/2]).
%Points 是投掷点的个数 Cores是核数,为2的幂
start(Points,Cores)
->spawn(fun()->parent_proces(Points,Cores) end),
io:format("").parent_proces(Points,Cores) ->
Poin...
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其他好文 时间:
2015-04-20 17:06:16
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155
题目如下:Givennpoints on a 2D plane, find the maximum number of points that lie on the same straight line.再简单不过的一题了,懒得写解释直接上代码了。/** * Definition for a poi...
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其他好文 时间:
2015-04-17 21:45:48
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110
SIFT(Scale-invariant feature transform)是一种检测局部特征的算法,该算法通过求一幅图中的特征点(interest points,or corner points)及其有关scale 和 orientation 的描述子得到特征并进行图像特征点匹配,获得了良好效果...
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其他好文 时间:
2015-04-17 13:01:55
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146
http://blog.csdn.net/gisfarmer/article/details/3736452Chart饼状图,每根柱子的宽度:int a = Chart1.Series["Series1"].Points.Count; Chart1.Series["Series1"].CustomP...
点的绘制。:glVertex*();星号表示函数要有后缀该函数 需要放在glBegin函数和glEnd函数之间,glBegin函数的向量指定绘制图元的类型,而glEnd函数没有参数,例如:glBegin(GL_POINTS);glVertex3f(0.0f,0.0f,0.0f);glVertex(1...
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其他好文 时间:
2015-04-16 11:59:05
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85
题目大意:从坐标(0,0,0)处观察到所有在(n,n,n)范围内的点的个数,如果一条直线上出现多个点,除了第一个,后面的都视为被遮挡了这题目稍微推导一下可得知 gcd(x,y,z) = 1的点是可观察到的,若三者的gcd>1,则这个点之前必然出现了一个(x/gcd(x,y,z) , y/gcd(x,...
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其他好文 时间:
2015-04-14 14:23:35
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131
miktorik ros IPSec Dynamic End points
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其他好文 时间:
2015-04-14 01:58:47
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167
Edward has 2n points on the plane conveniently labeled with 1,2,…,2n. Each point is connected exactly with another point by a segment.
Edward finds that some segments intersecting with some others. S...
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其他好文 时间:
2015-04-13 21:00:59
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233
Pattern lock security is generally used in Android handsets instead of a password. The pattern lock can be set by joining points on a 3 × 3 matrix in ...
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其他好文 时间:
2015-04-13 14:24:32
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108
Pattern lock security is generally used in Android handsets instead of a password. The pattern lock can be set by joining points on a 3 × 3 matrix in a chosen order. The points of the
matrix are reg...
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其他好文 时间:
2015-04-12 22:44:13
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204