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ajax 应用
function UpdateSubjectProductNum() { var arraySubjectNo = ''; $("input[name='SubjectNoCheckBox']").each(function () { ...
分类:其他好文   时间:2014-08-04 14:00:17    阅读次数:143
[LeetCode] Populating Next Right Pointers in Each Node II
Follow up for problem "Populating Next Right Pointers in Each Node".What if the given tree could be any binary tree? Would your previous solution stil...
分类:其他好文   时间:2014-08-04 13:32:57    阅读次数:184
N-Queens leetcode
Then-queens puzzle is the problem of placingnqueens on ann×nchessboard such that no two queens attack each other.Given an integern, return all distinc...
分类:其他好文   时间:2014-08-04 13:31:07    阅读次数:250
【802.3ad学习】LAG上的协商
选择一个LAG 每个端口都会被LAG上的membership选择,每个membership是由设备上唯一的LAG ID进行标识的 43.3.7 Selecting a Link Aggregation Group Each port is selected for membership in the...
分类:其他好文   时间:2014-08-04 10:57:57    阅读次数:279
工作中的一些问题总结
//获取关键字 var arr = []; $(".keyword_w span").each(function (i, e) { arr.push($(e).text().s...
分类:其他好文   时间:2014-08-04 10:41:16    阅读次数:187
Populating Next Right Pointers in Each Node II leetcode java
题目:Follow up for problem "Populating Next Right Pointers in Each Node".What if the given tree could be any binary tree? Would your previous solution ....
分类:编程语言   时间:2014-08-04 10:31:57    阅读次数:239
js jquery 结束循环
js 中跳出循环用break,结束本次循环用continue,jquery 中each循环 跳出用return true,或者return false,下面的代码的本意是输入组名查找组id,如果没有找到返回'nofind',在实际执行过程中,当找到组id的时候,执行了 return n.PLM_ID...
分类:Web程序   时间:2014-08-04 10:28:46    阅读次数:221
leetcode-Partition List
Given a linked list and a value x, partition it such that all nodes less than x come before nodes greater than or equal to x. You should preserve the original relative order of the nodes in each of...
分类:其他好文   时间:2014-08-03 23:28:56    阅读次数:261
[LeetCode] Triangle('Bottom-up' DP)
Given a triangle, find the minimum path sum from top to bottom. Each step you may move to adjacent numbers on the row below.For example, given the fol...
分类:其他好文   时间:2014-08-03 22:59:56    阅读次数:259
LeetCode——Populating Next Right Pointers in Each Node
题目: 给定一个二叉树(假设是完全二叉树),把每个节点的next指针指向其右侧节点。 思路:首先想到的是,层序遍历树,在遍历的同时添加节点对右侧节点的指针。 另一种简洁的方法是采用递归来实现,间单直观。...
分类:其他好文   时间:2014-08-03 15:23:45    阅读次数:246
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