Problem 34
145 is a curious number, as 1! + 4! + 5! = 1 + 24 + 120 = 145.
Find the sum of all numbers which are equal to the sum of the factorial of their digits.
Note: as 1! = 1 and 2! = 2 are...
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其他好文 时间：
2014-08-25 11:59:14
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243
Given a digit string, return all possible letter combinations that the number could represent.A mapping of digit to letters (just like on the telephon...
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其他好文 时间：
2014-08-23 18:53:01
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180
Description
Problem J
Bits
Input: Standard Input
Output: Standard Output
A bit is a binary digit, taking a logical value of either "1" or "0" (also referred to as "true" or "false" respecti...
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其他好文 时间：
2014-08-22 22:35:36
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278
Problem 32
We shall say that an n-digit number is pandigital if it makes use of all the digits 1 to n exactly once; for example, the 5-digit
number, 15234, is 1 through 5 pandigital.
The produ...
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其他好文 时间：
2014-08-22 16:23:19
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178
Problem 33
The fraction 49/98 is a curious fraction, as an inexperienced mathematician in attempting to simplify it may incorrectly believe that49/98 = 4/8, which is correct, is obtained by cance...
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其他好文 时间：
2014-08-22 16:17:19
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172
原题：
Given a digit string, return all possible letter combinations that the number could represent.
A mapping of digit to letters (just like on the telephone buttons) is given below.
Input...
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其他好文 时间：
2014-08-21 19:30:24
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225
Problem 30
Surprisingly there are only three numbers that can be written as the sum of fourth powers of their digits:
1634 = 14 + 64 + 34 + 44
8208 = 84 + 24 + 04 + 84
9474 = 94 + 44 + 74 + 44...
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其他好文 时间：
2014-08-21 09:48:04
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251
题目链接：
huangjing
思路：
这个题目想到dfs很容易，但是纠结在这么像杨辉三角一样计算那些值，这个我看的队友的，简直厉害，用递归计算出杨辉三角顶端的值。。。。具体实现详见代码。。。
题目：
Language:
Default
Backward Digit Sums
Time Limit: 1000MS
Memo...
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其他好文 时间：
2014-08-20 21:12:12
阅读次数：
254
//模幂运算，而且求个位，一直求10的模
# include
# include
# include
using namespace std;
__int64 Pow(__int64 m,__int64 n)
{
__int64 p=1;
while(n)
{
if(n%2)
p=p*m%10;
n/=2;
...
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Web程序 时间：
2014-08-20 18:02:42
阅读次数：
175
Description
FJ and his cows enjoy playing a mental game. They write down the numbers from 1 to N (1 <= N <= 10) in a certain order and then sum adjacent numbers to produce a new list with one fewer...
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其他好文 时间：
2014-08-20 10:33:36
阅读次数：
256
