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android 细节之An internal error occurred during: "Launching New_configuration".
今天在导入公司的一个小demo时候发现了一个很有意思的错误。 An internal error occurred during: "Launching New_configuration". Path for project must have only one segment. 于是上网搜寻了一下怎么解决: 具体的解决方法有两种: 一、Run Confi...
分类:移动开发   时间:2014-08-26 00:33:05    阅读次数:240
CF-85D-Sum of Medians(线段树)
In one well-known algorithm of finding the k-th order statistics we should divide all elements into groups of five consecutive elements and find the median of each five. A median is called the middl...
分类:其他好文   时间:2014-08-25 22:50:55    阅读次数:297
linux驱动程序之电源管理之标准linux休眠与唤醒机制分析(一)
1. Based on linux2.6.32, only for mem(SDR)2. 有兴趣请先参考阅读: 电源管理方案APM和ACPI比较.docLinux系统的休眠与唤醒简介.doc3. 本文先研究标准linux的休眠与唤醒,android对这部分的增改在另一篇文章中讨论4. 基于手上的一个...
分类:系统相关   时间:2014-08-25 22:40:55    阅读次数:403
LeetCode: Best Time to Buy and Sell Stock
LeetCode: Best Time to Buy and Sell StockSay you have an array for which the ith element is the price of a given stock on day i.If you were only permi...
分类:其他好文   时间:2014-08-25 22:35:34    阅读次数:261
LeetCode: Valid Palindrome
LeetCode: Valid PalindromeGiven a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases. For example,"A...
分类:其他好文   时间:2014-08-25 22:31:25    阅读次数:216
POJ 1144 Network
NetworkTime Limit: 1000msMemory Limit: 10000KBThis problem will be judged onPKU. Original ID:114464-bit integer IO format:%lld Java class name:MainA T...
分类:Web程序   时间:2014-08-25 22:28:34    阅读次数:340
skynet源码学习 - 从全局队列中弹出/压入一个消息队列过程
学习云风的skynet源码,简单记录下。 void skynet_globalmq_push(struct message_queue * queue) { struct global_queue *q= Q; uint32_t tail = GP(__sync_fetch_and_add(&q->tail,1)); // only one thread can set the sl...
分类:Web程序   时间:2014-08-25 21:11:04    阅读次数:499
HDU 3836 Equivalent Sets
Equivalent SetsTime Limit: 4000msMemory Limit: 104857KBThis problem will be judged onHDU. Original ID:383664-bit integer IO format:%I64d Java class na...
分类:其他好文   时间:2014-08-25 21:08:34    阅读次数:243
poj 3083 Children of th
#include #include#includeusing namespace std;int n,m;int r[4][2]= {{0,-1},{1,0},{0,1},{-1,0}};int l[4][2]= {{0,1},{1,0},{0,-1},{-1,0}};int vis[50][50]...
分类:其他好文   时间:2014-08-25 20:48:44    阅读次数:200
Unique Paths
A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below).The robot can only move either down or right at any po...
分类:其他好文   时间:2014-08-25 20:43:44    阅读次数:237
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