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ZOJ 3705 Applications 模拟
#pragma comment(linker, "/STACK:1024000000,1024000000")#include#include#include#include#include#include#include#include#include#include#include#includ...
分类:移动开发   时间:2014-05-08 19:33:18    阅读次数:493
zoj 1608 Two Circles and a Rectangle 判断两个圆是否能放入一个矩形中
题目来源:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=608分析:两个圆放到矩形的临界点图为:其中a为长, b为宽, r1 > r2红色三角形的三边长分别为:x = a - (r1 +r2)y = b - (r1 + r2)z...
分类:其他好文   时间:2014-05-08 14:17:58    阅读次数:377
JAVA的RSS处理
一:什么是RSSRSS(really simple syndication) :网页内容聚合器。RSS的格式是XML。必须符合XML 1.0规范。RSS的作用:订阅BLOG,订阅新闻二:RSS的历史版本:http://blogs.law.harvard.edu/tech/rssVersionHist...
分类:编程语言   时间:2014-05-08 13:08:55    阅读次数:671
Attaching detached POCO to EF DbContext - simple and fast
IntroductionRecently I was playing around with Entity Framework (EF) and evaluating it for some projects. I had a very hard time figuring out how to a...
分类:数据库   时间:2014-05-08 13:05:33    阅读次数:678
Pat(Advanced Level)Practice--1060(Are They Equal)
Pat1060代码 题目描述: If a machine can save only 3 significant digits, the float numbers 12300 and 12358.9 are considered equal since they are both saved as 0.123*105 with simple chopping. Now given...
分类:其他好文   时间:2014-05-08 02:07:49    阅读次数:452
url传值乱码 encode转码和decode解码
在java开发中经常遇见汉字传输乱码的问题,特别是在夹杂着javascript和ajax的情况。最近在用android做一个手持终端的应用,移动终端需要调用服务器上部署的action,我采用post传值方式调用,关键代码如下: FinalHttp fh = new FinalHttp(); tr.....
分类:其他好文   时间:2014-05-08 01:02:06    阅读次数:555
[dfs] zoj 3736 Pocket Cube
题目链接: http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3736 Pocket Cube Time Limit: 2 Seconds      Memory Limit: 65536 KB Pocket Cube is a 3-D combination puzzle. It is a 2 ×...
分类:其他好文   时间:2014-05-07 23:53:24    阅读次数:709
meta program (1) swap_iter
开始学习模板元编程了 #include #include #include #include #include "boost/assign/list_of.hpp" #include "boost/type_traits/is_const.hpp" #include "boost/type_traits/is_reference.hpp" #include "boost/type_tr...
分类:其他好文   时间:2014-05-07 16:32:27    阅读次数:358
[再寄小读者之数学篇](2014-04-23 行列式的导数)
设 $A(t)=(a_{ij}(t))$ 中每个 $a_{ij}(t)$ 都是可导的, 则 $$\bex \cfrac{\rd}{\rd t}|A(t)|=|A|\tr \sez{A^{-1}\cfrac{\rd A}{\rd t}}. \eex$$
分类:其他好文   时间:2014-05-07 10:52:10    阅读次数:206
android Beam
Beaming NDEF Messages to Other Devices Android Beam allows simple peer-to-peer data exchange between two Android-powered devices. The application that wants to beam data to another device must be in ...
分类:移动开发   时间:2014-05-06 23:21:48    阅读次数:620
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