@echo offrem 把当前运行的目录添加到系统环境变量里面rem 环境win7_64 2014/7/29rem 获得当前目录 set fileName=%0 set fileDir=%fileName:~1,-12%rem 查询注册表中对应的环境变量 for /f "tokens=3*" %%...
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其他好文 时间:
2014-07-29 16:50:12
阅读次数:
224
不会做啊 这么水的dp =-=怨死 。。。。 touch me我下面内容 都是来自 传送dp[i][j]表示前i个月最后一个月的总人数为j所花的最小费用状态移动方程:dp[i][j] = min{dp[i-1][k] + cost[i][j]},其中cost[i][j]是第i月的花费,1~...
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其他好文 时间:
2014-07-29 16:39:42
阅读次数:
244
①起始日期不能大于结束日期,最小日期为当天,最大日期为结束日期<b>起始日期</b><inputid="starttime"type="text"name="startTime"class="WdateWtime"style="float:left"onClick="WdatePicker({minDate:newDate(),maxDate:‘#F{$dp.$D(\‘endtime\‘)}‘})">&l..
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其他好文 时间:
2014-07-29 15:27:29
阅读次数:
285
Description
Before ACM can do anything, a budget must be prepared and the necessary financial support obtained. The main income for this action comes from Irreversibly Bound Money (IBM). The idea beh...
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其他好文 时间:
2014-07-29 15:08:28
阅读次数:
232
Problem Description
Alice and Bob are playing a game. There are two piles of cards. There are N cards in each pile, and each card has a score. They take turns to pick up the top or bottom card from...
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其他好文 时间:
2014-07-29 15:03:28
阅读次数:
248
Problem Description
ACboy has N courses this term, and he plans to spend at most M days on study.Of course,the profit he will gain from different course depending on the days he spend on it.How to ar...
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其他好文 时间:
2014-07-29 14:57:28
阅读次数:
292
Description
We all love recursion! Don't we?
Consider a three-parameter recursive function w(a, b, c):
if a
1
if a > 20 or b > 20 or c > 20, then w(a, b, c) returns:
w(20, 20, 20)
...
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其他好文 时间:
2014-07-29 14:54:08
阅读次数:
278
n个数字,范围是1-s,需要将1-s分成k段,使得每个数字必然只属于一段。分别计算每段的正序对,求和即为答案,现在需要让这个和最小,求最小值...
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其他好文 时间:
2014-07-29 14:51:42
阅读次数:
269
Problem Description
After months of hard working, Iserlohn finally wins awesome amount of scholarship. As a great zealot of sneakers, he decides to spend all his money on them in a sneaker store.
...
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其他好文 时间:
2014-07-29 14:42:05
阅读次数:
273
题意:给一个方阵,求从左上角出到右下角(并返回到起点),经过每个点一次不重复,求最大获益(走到某处获得改点数值),下来时每次只能向右或向下,反之向上或向左。
俩种解法:
1 费用流法:思路转化:从左上角流出2的流量,(表示走俩条路),归于右下角,可以走就有边(右和下),权为负的费用,源点连起点,汇点连终点,流量为2. 除源汇外所有点一分为2,Y向X对应点有流量1的边,之前边为X到Y的(原图)...
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编程语言 时间:
2014-07-29 14:40:38
阅读次数:
310