Given an integer, write a function to determine if it is a power of two.public class Solution { //注意0和负数都返回false!!! /*public boolean isP...
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其他好文 时间:
2015-08-08 17:59:22
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149
最近写项目总是会在VS中打开一堆的文件,横向排列的方式已经满足不了我了。在网上看了一个视频,他的选项卡是竖着排列的,于是各种百度,VS的扩展和更新里面各种搜。终于让我找到他用的工具了。先看一下最后的效果。插件是这个:Productivity Power Tools 2013,在VS的扩展和更新里.....
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其他好文 时间:
2015-08-08 06:29:31
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154
Power Strings
Time Limit: 3000MS
Memory Limit: 65536K
Total Submissions: 37564
Accepted: 15532
Description
Given two strings a and b we define a*b to be their concatena...
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其他好文 时间:
2015-08-07 22:28:09
阅读次数:
92
Time Limit: 3000MS
Memory Limit: 65536K
Total Submissions: 37439
Accepted: 15467
Description
Given two strings a and b we define a*b to be their concatenation. For example, ...
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其他好文 时间:
2015-08-07 20:16:01
阅读次数:
78
学算法之后,Ac的第一道题。
分析:当i%(i-p[i])==0&&p[i]!=0时,字符串结束循环。并且,偱环节长度为 i-p[i],循环次数为
i/(i-p[i]).
#include
#include
int len;
int p[1000010];
char str[1000010];
void getp()
{
int i=0,j=-1;
p[i]=j;
w...
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其他好文 时间:
2015-08-07 20:08:14
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125
Power Strings
Time Limit : 6000/3000ms (Java/Other) Memory Limit : 131072/65536K (Java/Other)
Total Submission(s) : 70 Accepted Submission(s) : 27
Problem Description
Given two strings a and ...
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其他好文 时间:
2015-08-07 20:06:03
阅读次数:
124
Description
Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "abcdef". If we think of concatenation as multiplication, exponenti...
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其他好文 时间:
2015-08-07 20:04:56
阅读次数:
132
Power StringsDescriptionGiven two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "abcdef"...
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其他好文 时间:
2015-08-07 18:53:14
阅读次数:
83
Power Strings
Time Limit: 3000MS
Memory Limit: 65536K
Total Submissions: 37379
Accepted: 15443
Description
Given two strings a and b we define a*b to be their concatena...
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其他好文 时间:
2015-08-07 13:22:56
阅读次数:
97
本文是在学习中的总结,欢迎转载但请注明出处:http://blog.csdn.net/pistolove/article/details/47334243
Given an integer, write a function to determine if it is a power of two.
思路:
(1)题意为给定一个正整数,判断该正整数是否为2的幂。
(2)该题属于Lettcode中的简单题。只需循环判断正整数N对2求余是否为0,如果不为0,返回false;如果...
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其他好文 时间:
2015-08-07 11:20:29
阅读次数:
113