http://poj.org/problem?id=3517
讲解
n个人,编号为1~n,每次数到m的人出圈,最后一个出圈的人的编号。
f[1] = 0;
for(int i = 2; i <= n; i++)
{
f[i] = ( f[i-1] + m)%i;
}
printf("%d\n",f[n]+1);
这里第一次出圈的人的编号是m,然后...
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