我不是为了输赢，我就是认真！但不管怎么样，我们的主题你是不能换壁纸的！我碰不上右上角的图标，单手操作有个屁用！我们优秀的企业家都是这样马不停蹄的。see you
soon“杜乡微笑”（Duchenne smile）一种是同时用到嘴部与眼部周围肌肉的这种微笑才是发自内心的真诚微笑。
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其他好文 时间：
2014-05-26 02:15:30
阅读次数：
186
you should consider creating a custom View
component and drawing with a Canvas inView.onDraw(). The most convenient aspect
of doing so is that the And...
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其他好文 时间：
2014-05-26 00:05:06
阅读次数：
327
QGtkStyle could not resolve GTK. Make sure you
have installed the proper libraries.sudo apt-get install --reinstall
gtk2-engines-murrine:i386sudo add-...
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其他好文 时间：
2014-05-25 23:45:25
阅读次数：
276
Sencha removed the refreshFn from the pullrefresh
plugin in ST 2.2. Here is an user extension with gives the old functionality
back to you./** * This ...
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其他好文 时间：
2014-05-25 19:39:42
阅读次数：
289
Problem Description
We have a special convex that all points have the same distance to origin point.
As you know we can get N segments after linking the origin point and the points on the convex. ...
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其他好文 时间：
2014-05-25 09:50:19
阅读次数：
217
A palindromic number or numeral palindrome is a 'symmetrical' number like 16461 that remains the same when its digits are reversed. In this problem you will be given two integers i j, you have to find...
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其他好文 时间：
2014-05-25 07:41:08
阅读次数：
253
【题目】
Given an integer n, generate a square matrix filled with elements from 1 to n2 in spiral order.
For example,
Given n = 3,
You should return the following matrix:
[
[ 1, 2, 3 ],
[ 8, 9, 4 ],
[ 7, 6, 5 ]
]
【题意】
给定整数n, 将1,2,3...nxn个数按螺旋旋转的方式填入n...
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其他好文 时间：
2014-05-25 07:08:17
阅读次数：
235
Problem Description
We have a special convex that all points have the same distance to origin point.
As you know we can get N segments after linking the origin point and the points on the convex. ...
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其他好文 时间：
2014-05-25 06:55:54
阅读次数：
188
原文地址：http://developer.android.com/training/scheduling/alarms.html
Alarms (based on the AlarmManager class)
give you a way to perform time-based operations outside the lifetime of your applicati...
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移动开发 时间：
2014-05-25 04:31:48
阅读次数：
488
题目来源：UVa 10294 Arif in Dhaka (First Love Part 2)
题意：n颗珠子t种颜色 求有多少种项链和手镯 项链不可以翻转 手镯可以翻转
思路：Polya定理 题目就是求等价类 项链只能旋转 手镯可以旋转也可以翻转
根据定理 等价类的数量等于各个置换f的t^m(f)的平均数 m(f)是置换的循环节数 下面每次t^x x都是循环节数
下面考虑手镯 旋转翻...
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其他好文 时间：
2014-05-24 19:52:10
阅读次数：
258
