Problem Description
PM Room defines a sequence A = {A1, A2,..., AN}, each of which is either 0 or 1. In order to beat him, programmer Moor has to construct another sequence B = {B1, B2,... , BN}
of...
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其他好文 时间:
2014-08-07 23:18:54
阅读次数:
308
Room and MoorProblem DescriptionPM Room defines a sequence A = {A1, A2,..., AN}, each of which is either 0 or 1. In order to beat him, programmer Moor...
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其他好文 时间:
2014-08-07 22:53:15
阅读次数:
293
Knight Moves
Description
Background
Mr Somurolov, fabulous chess-gamer indeed, asserts that no one else but him can move knights from one position to another so fast. Can you beat him?
The P...
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其他好文 时间:
2014-07-26 17:23:32
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590
maven中手动去更新jar包,是一件比较繁琐麻烦的事情,使用Range Dependency则可以省去这一步骤。 部分jar包可能会自动升级到beat版本! 官方说明文档:Dependency Version Ranges Range Meaning (...
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其他好文 时间:
2014-07-21 10:30:10
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243
题目,求一个连续的数组,最大连续和。
(一)O(n3)算法:
利用穷举法的思想,这种方法的效率最差。
代码如下:
#include
#include
#include
#include
using namespace std;
const int MAXN = 1000;
int A[MAXN], n;
int maxsum(int *A, int n) {
int beat...
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其他好文 时间:
2014-07-02 09:15:50
阅读次数:
349