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Java for LeetCode 074 Search a 2D Matrix
Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:Integers in each row are sorted fr...
分类:编程语言   时间:2015-05-17 13:39:30    阅读次数:148
Java for LeetCode 073 Set Matrix Zeroes
Given a m x n matrix, if an element is 0, set its entire row and column to 0. Do it in place.解题思路:用两个boolean数组row col表示行列是否有零即可,JAVA实现如下: public void ...
分类:编程语言   时间:2015-05-17 10:38:44    阅读次数:179
ZOJ 3646 Matrix Transformer 二分匹配,思路,经典 难度:2
http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=4836因为要使对角线所有元素都是U,所以需要保证每行都有一个不同的列上有U,设(i,j)的位置是U,以U为边,连接点i和点j+n,也即连接行点和列点,最大匹配为n则必定有解,否则必...
分类:其他好文   时间:2015-05-17 02:03:13    阅读次数:138
Android Paint、Canvas、Matrix使用讲解(一、Paint)
http://blog.csdn.net/tianjian4592/article/details/44336949好了,前面主要讲了Animation,Animator 的使用,以及桌面火箭效果和水波纹效果,分别使用android框架和自己绘制实现,俗话说,工欲善其事,必先利其器,接下来几篇文章主...
分类:移动开发   时间:2015-05-16 17:55:39    阅读次数:165
Maximal Rectangle
地址:https://oj.leetcode.com/problems/maximal-rectangle/Given a 2D binary matrix filled with 0's and 1's, find the largest rectangle containing all ones...
分类:其他好文   时间:2015-05-16 11:54:21    阅读次数:176
leetcode_Spiral Matrix II
这题看起来是很复杂,做起来也确实挺复杂的。但是呢,这题并不是非常非常难,只是控制逻辑让人很抓狂罢了。 colStart,colEnd,rowStart,rowEnd,num=0 1.colStart<colEnd 为arr[row][colStart]~arr[row][colEnd-1]赋值num++; 2.rowStartcolStart 为arr[rowLen-1-row][...
分类:其他好文   时间:2015-05-16 10:34:09    阅读次数:88
POJ 题目2155 Matrix(二维树状数组)
Matrix Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 20303   Accepted: 7580 Description Given an N*N matrix A, whose elements are either 0 or 1. A[i, j] me...
分类:编程语言   时间:2015-05-16 09:11:24    阅读次数:166
【转】What is an SDET? Part 2 – Skill Matrix of SDET
Part 2 of What is an SDET, skills matrix of SDET.
分类:其他好文   时间:2015-05-16 01:27:21    阅读次数:114
Java for LeetCode 059 Spiral Matrix II
Given an integer n, generate a square matrix filled with elements from 1 to n2 in spiral order. For example,Given n = 3,You should return the followin...
分类:编程语言   时间:2015-05-15 21:05:11    阅读次数:176
BestCoder#40 C Tom and matrix
传送门在这里 题意:求Sum(C[i][j]) (x1 思路:由c[i][j]=c[i-1][j-1]+c[i-1][j]可知Sum(C[i][k]) = C[b+1][k+1]-C[a][k+1] (a Lucas定理:C[n][m]%p=C[n/p][m/p]*C]n%p][m%p]%p 令a=n%p,b=m%p, 则C[a][b]=a!/(b!*(a-b)!) 由于b!*(a-b...
分类:其他好文   时间:2015-05-15 17:49:41    阅读次数:114
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