https://gennadny.wordpress.com/2014/11/ Since SQL Server 7.0, SQL Server has its own scheduling mechanism, In SQL 7.0 and 2000 it was called UMS (User ...
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数据库 时间:
2017-06-11 00:57:30
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385
题目 URL:https://leetcode.com/problems/longest-substring-without-repeating-characters 解法 一、Hash by HashMap 核心思想是,判断字符是否在 HashMap 中,如果是,那么计算当前不重复字串的长度,和之 ...
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其他好文 时间:
2017-06-11 00:26:47
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197
Quartz 介绍 Quartz is a full-featured, open source job scheduling service that can be integrated with, or used along side virtually any Java application ...
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编程语言 时间:
2017-06-10 23:31:08
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269
problem: Given a string, find the length of the longest substring without repeating characters. For example, the longest substring without repeating l ...
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编程语言 时间:
2017-06-09 14:12:32
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137
Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1. Examples: Note: You may assume the ...
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其他好文 时间:
2017-06-09 00:52:12
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189
题目大意是传入一条字符串,计算出这样的这样一条子字符串,要求子字符串是原字符串的连续的某一段,且子字符串内不包含两个或两个以上的重复字符。求符合上面条件的字符串中最长的那一条的长度。 首先注意到任意一条无重复子字符串的任意子字符串应该也满足无重复这一特性。因此这个问题可以用动态规划解决。 需要先计算 ...
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其他好文 时间:
2017-06-04 16:51:58
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163
【题意】 Given a string, find the length of the longest substring without repeating characters. For example, the longest substring without repeating lette ...
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其他好文 时间:
2017-05-30 15:57:52
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117
题目: Given a string, find the length of the longest substring without repeating characters. For example, the longest substring without repeating letter ...
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其他好文 时间:
2017-05-24 22:45:09
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265
http://wzping.iteye.com/blog/468263 1、定义一个JOB <!-- 使用pojo来做job,指定pojo和method --> <bean id="jobDetail" class="org.springframework.scheduling.quartz.Met ...
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编程语言 时间:
2017-05-24 12:48:55
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257
Problem statement: Given a string that consists of only uppercase English letters, you can replace any letter in the string with another letter at mos ...
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其他好文 时间:
2017-05-24 09:54:32
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227