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Oracle 11g RAC database on ASM, ACFS or OCFS2
I see a lot of questions on shared file systems that can be used when people move from single instance to Oracle RAC database and Grid Infrastructure....
分类:数据库   时间:2015-01-19 22:31:09    阅读次数:290
jquery mini ui 学习
1.mini.parse();将html标签解析为miniui控件。解析后,才能使用mini.get获取到控件对象。2.mini.get(id);根据id获取控件对象.3.grid.load();3.0 load ( params, success, fail )3.1params:Object。参...
分类:Web程序   时间:2015-01-19 17:12:01    阅读次数:902
Grid_Oracle Grid单节点安装ASM和Instance(案例)
2014-07-08 Created By BaoXinjianThanks and Regardshttp://blog.itpub.net/21471457/viewspace-1114903/http://blog.163.com/donfang_jianping/blog/static/13...
分类:数据库   时间:2015-01-18 11:45:55    阅读次数:165
EXTJS 4.2 资料 控件之Grid 那些事
最近在学习Extjs4.2 ,积累文章,看得不错,再此留年://表格数据最起码有列、数据、转换原始数据这3项 Ext.onReady(function(){ //定义列 var columns = [ {header:'编号',dataIndex:'id',w...
分类:Web程序   时间:2015-01-17 09:58:06    阅读次数:274
Dungeon Game Leetcode Python
The demons had captured the princess (P) and imprisoned her in the bottom-right corner of a dungeon. The dungeon consists of M x N rooms laid out in a 2D grid. Our valiant knight (K) was initially p...
分类:编程语言   时间:2015-01-17 08:50:50    阅读次数:206
hdu 2571 命运(水DP)
题意:M*N的grid,每个格上有一个整数。小明从左上角(1,1)打算走到右下角(M,N)。每次可以向下走一格,或向右走一格,或向右走到当前所在列的倍数的列的位置上。即:若当前位置是(i,j),可以走到(i,k*j)问取走的最大和是多少。思路:水DP。。。边界的初始化要考虑。(因为有负数)。代码:i...
分类:其他好文   时间:2015-01-16 23:44:20    阅读次数:155
Ext.grid.GridPanel数据转json
var count = docAdGrid.getStore().getCount();var jsonArray = [];for (var i = 0; i < count; i++) { var record = docAdGrid.getStore().getAt(i); ...
分类:Web程序   时间:2015-01-16 18:34:07    阅读次数:127
jqgrid的外观重绘
1、如果你想随时更改jqGrid的外观和列,可以先将jqGrid卸载掉再重新加载:$(grid).GridUnload(); $("#list_server_table").trigger("reloadGrid");2、jqGrid的列:colName、colModel其实是 json 格式的数据...
分类:其他好文   时间:2015-01-16 16:24:21    阅读次数:437
LeetCode-Unique Paths
A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below). The robot can only move either down or right at any point in time. The robot is trying to reach the ...
分类:其他好文   时间:2015-01-15 23:56:23    阅读次数:294
[C++]LeetCode: 97 Word Search (深度优先搜索)
题目: Given a 2D board and a word, find if the word exists in the grid. The word can be constructed from letters of sequentially adjacent cell, where "adjacent" cells are those horizontally or ver...
分类:编程语言   时间:2015-01-15 16:14:27    阅读次数:301
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