area
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 623 Accepted Submission(s): 233
Problem Description
小白最近被空军特招为飞行员,参与一项实战演习。演习的内...
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其他好文 时间:
2014-05-07 16:11:04
阅读次数:
473
RPG的错排
Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 6746 Accepted Submission(s): 2738
Problem Description
今年暑假杭电ACM集训队第一次组成女生队,其中...
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其他好文 时间:
2014-05-07 15:59:59
阅读次数:
366
LOOPS
Time Limit: 15000/5000 MS (Java/Others) Memory Limit: 125536/65536 K (Java/Others)
Total Submission(s): 1651 Accepted Submission(s): 653
Problem Description
Akemi Homura is a M...
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其他好文 时间:
2014-05-07 15:58:07
阅读次数:
290
本文出自:http://blog.csdn.net/svitter
原题:http://poj.org/problem?id=1141
题意:输出添加括号最少,并且使其匹配的串。
题解: dp [ i ] [ j ] 表示添加括号的个数, pos[ i][ j ] 表示i, j中哪个位置分开,使得两部分分别匹配。
初始值置dp [ i ] [ i ] = 1; 如果只有一个括号,...
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其他好文 时间:
2014-05-07 15:17:21
阅读次数:
367
I had a similar problem when running a spring
web application in an Eclipse managed tomcat. I solved this problem by adding
maven dependencies in the ...
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移动开发 时间:
2014-05-07 14:33:12
阅读次数:
486
Problem B: Fire!Joe works in a maze. Unfortunately,
portions of the maze have caught on fire, and the owner of the maze neglected to
create a fire esc...
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其他好文 时间:
2014-05-07 13:28:07
阅读次数:
312
find the most comfortable road
Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 3369 Accepted Submission(s): 1437
Problem Descriptio...
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其他好文 时间:
2014-05-07 12:18:52
阅读次数:
306
Ignatius and the Princess III
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 11896 Accepted Submission(s): 8424
Problem Descript...
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其他好文 时间:
2014-05-07 11:58:46
阅读次数:
403
Aeroplane chess
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 1122 Accepted Submission(s): 762
Problem Description
Hzz loves a...
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其他好文 时间:
2014-05-07 11:51:37
阅读次数:
330
题目;http://poj.org/problem?id=3182题意:一个棋盘中间有一个联通块,给你一个起点让你从起点开始绕联通块外围一圈并回到起点,求最小步数。分析:首先根据数据的范围比较小,所以觉得应该是搜索,而且是BFS。朴素的想法是从起点开始BFS
8个方向扩展,不过这样肯定要跪。注意到这...
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其他好文 时间:
2014-05-07 11:18:41
阅读次数:
330