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Reverse Integer
Reverse digits of an integer.Example1:x = 123, return 321Example2:x = -123, return -321Have you thought about this?Here are some good questions to ask...
分类:其他好文   时间:2014-05-01 01:20:59    阅读次数:334
hdu 2199:Can you solve this equation?(二分搜索)
Can you solve this equation?Time Limit: 2000/1000 MS (Java/Others)Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 7493Accepted Submissio...
分类:其他好文   时间:2014-05-01 00:41:54    阅读次数:356
rlwrap安装报错You need the GNU readline 解决方法
首先大家肯定知道rlwrap是干什么的?在linux以及unix中,sqlplus的上下左右、回退无法使用,会出现乱码情况。而rlwrap这个软件就是用来解决这个的。这个错误曾经困扰我很久很久!下载readline安装,安装好readline 还是无法运行rlwrap的安装程序在网上搜寻很久才找到一...
分类:其他好文   时间:2014-04-30 23:35:02    阅读次数:587
Pat(Advanced Level)Practice--1063(Set Similarity)
Pat1063代码 题目描述: Given two sets of integers, the similarity of the sets is defined to be Nc/Nt*100%, where Nc is the number of distinct common numbers shared by the two sets, and Nt is the to...
分类:其他好文   时间:2014-04-29 13:44:20    阅读次数:325
Leetcode:Minimum Path Sum 最小路径和
Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path. Note: You can only move either down or right at...
分类:其他好文   时间:2014-04-28 10:46:41    阅读次数:311
poj 3468 A Simple Problem with Integers
A Simple Problem with Integers Time Limit: 5000MS   Memory Limit: 131072K Total Submissions: 55626   Accepted: 16755 Case Time Limit: 2000MS Description You have N...
分类:其他好文   时间:2014-04-28 10:23:41    阅读次数:282
避免nrpe端进程监控多个接口
为了避免目标端nrpe进程监控多个接口而造成的安全漏洞。有必要固定服务端的地址,对nrpe.cfg配置中,有下列一行介绍 #SERVER ADDRESS # Address that nrpe should bind to in case there are more than one interface # and you do not want nrpe to bind on all in...
分类:其他好文   时间:2014-04-27 22:36:17    阅读次数:454
java Annotation 自定义实例
Defining annotations Here is the definition of the annotation above. You can see that annotation definitions look a lot like interface definitions.  In fact, they compile to class files like any oth...
分类:编程语言   时间:2014-04-27 21:47:05    阅读次数:348
hdu1211
RSA is one of the most powerful methods to encrypt data. The RSA algorithm is described as follow: > choose two large prime integer p, q > calculate n = p × q, calculate F(n) = (p - 1) × (q - 1) ...
分类:其他好文   时间:2014-04-27 21:37:59    阅读次数:315
java Annotation原理
Annotations are one of the fundamental language changes introduced in Java SE5. They provide information that you need to fully describe your program, but that cannot be expressed in Java. Thus, anno...
分类:编程语言   时间:2014-04-27 21:14:59    阅读次数:431
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