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Configurate root account
After having installed Ubuntu OS, you should update config file for root account. The commands are listed as follow:vi /etc/lightdm/lightdm.conf #open...
分类:其他好文   时间:2014-04-29 19:21:56    阅读次数:555
STM32之PWM君
PWM、、英语好的人估计又知道这三个大写字母代表哪三个英语单词了、小弟不才,就说中文意思好了:脉冲宽度调制,玩过飞思卡尔的人估计对PWM非常的不陌生吧、电机驱动需要PWM,控制舵机的转向需要PWM,总之、可以说,PWM,you are so good。 好了、、言归正传,广大的互联网的网友们,咱.....
分类:其他好文   时间:2014-04-29 18:56:12    阅读次数:524
Configurate vim tool
vim toolis a commom editor, for the sake of improving effeicient, it is necessary to configurate vim config file. The following comands will help you....
分类:其他好文   时间:2014-04-29 17:58:49    阅读次数:502
POJ 3356 AGTC(DP-最小编辑距离)
DescriptionLetxandybe two strings over some finite alphabetA. We would like to transformxintoyallowing only operations given below:Deletion:a letter i...
分类:其他好文   时间:2014-04-29 16:22:00    阅读次数:450
A quest for the full InnoDB status
When running InnoDB you are able to dig into the engine internals, look at various gauges and counters, see past deadlocks and the list of all open tr...
分类:数据库   时间:2014-04-29 15:41:04    阅读次数:686
悟以往只不谏,念来者之可追
1.To survive among the ordinary,you must be strong and independent!2.Be a unique person and develop skills so that nobody can replace you!3.Since nans...
分类:其他好文   时间:2014-04-29 15:37:58    阅读次数:567
Binary String Matching
Binary String Matching时间限制:3000ms | 内存限制:65535KB难度:3描述Given two strings A and B, whose alphabet consist only ‘0’ and ‘1’. Your task is only to tell ho...
分类:其他好文   时间:2014-04-29 15:02:00    阅读次数:564
《Cracking the Coding Interview》——第18章:难题——题目1
2014-04-29 00:56题目:不用算数运算,完成加法。解法:那就位运算吧,用加法器的做法就可以了。代码: 1 // 18.1 add two numbers wihout using arithmetic operator. 2 #include 3 using namespace std....
分类:其他好文   时间:2014-04-29 14:58:53    阅读次数:383
A Step-by-Step Guide to Your First AngularJS App
What is AngularJS?AngularJS is a JavaScript MVC framework developed by Google that lets you build well structured, easily testable, and maintainable f...
分类:移动开发   时间:2014-04-29 14:32:23    阅读次数:971
《Cracking the Coding Interview》——第18章:难题——题目9
2014-04-29 04:18题目:有一连串的数被读入,设计一个数据结构,能随时返回当前所有数的中位数。解法:用一个大顶堆,一个小顶堆将数分成数量最接近的两份,就能轻松得到中位数了。代码: 1 // 18.9 A stream of integers are passed to you, you....
分类:其他好文   时间:2014-04-29 14:16:52    阅读次数:423
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