Given a linked list, return the node where the cycle begins. If there is no cycle, returnnull.Follow up:Can you solve it without using extra space?Hid...
分类:
其他好文 时间:
2015-01-06 17:42:21
阅读次数:
123
题目:
Follow up for "Remove Duplicates":
What if duplicates are allowed at most twice?
For example,
Given sorted array A = [1,1,1,2,2,3],
Your function should return length = 5, and A is no...
分类:
编程语言 时间:
2015-01-06 15:41:57
阅读次数:
163
在创建Shader的时候,总是提示这个错误;本以为是定义分配的动态内存不足而导致;经过follow,排除此原因;最后经过了一番排查,才知道,是因为在加lib的顺序也会影响程序的运行;
将两个DX库(DX9 and DX11调了一下顺序,才搞定);
心得:在配置文件的时候,及时将一些不需要的配置删除,以免造成不必要的麻烦;
库文件(lib)的顺序会影响程序的执行;...
分类:
其他好文 时间:
2015-01-06 15:35:27
阅读次数:
126
The problem:Follow up for "Search in Rotated Sorted Array":What ifduplicatesare allowed?Would this affect the run-time complexity? How and why?Write a...
分类:
其他好文 时间:
2015-01-06 09:42:10
阅读次数:
185
题目:
You are given an n x n 2D matrix representing an image.
Rotate the image by 90 degrees (clockwise).
Follow up:
Could you do this in-place?
不使用额外的存储空间,完成N*N的图片的90度旋转(顺时针)
Answer 1: ...
分类:
编程语言 时间:
2015-01-05 16:47:49
阅读次数:
222
公司和学校事情比较多,隔了好几天没刷题,今天继续刷起来。题目:Given a linked list, return the node where the cycle begins. If there is no cycle, returnnull.Follow up:Can you solve i...
分类:
编程语言 时间:
2015-01-03 17:11:53
阅读次数:
193
Given a linked list, return the node where the cycle begins. If there is no cycle, return null.
Follow up:
Can you solve it without using extra space?
首先设圆环的长度为r,距离环口为a时相遇,环外的那一段的距离是b,那么有2(a+b)=a...
分类:
其他好文 时间:
2014-12-29 21:35:30
阅读次数:
248
Given a linked list, determine if it has a cycle in it.
Follow up:
Can you solve it without using extra space?
利用快慢指针
/**
* Definition for singly-linked list.
* class ListNode {
* int v...
分类:
其他好文 时间:
2014-12-29 21:35:23
阅读次数:
235
题目描述:
Follow up for "Unique Paths":
Now consider if some obstacles are added to the grids. How many unique paths would there be?
An obstacle and empty space is marked as 1 and 0 respectivel...
分类:
其他好文 时间:
2014-12-29 10:28:11
阅读次数:
183
-----------对目录操作----------------pocdata_exp_from_172.20.8.23_nscrmdb_20140907.02001、根据修改时间和当前时间比较、目录名称进行筛选,再直接删除find . -maxdepth 1 -follow -type d ! ....
分类:
其他好文 时间:
2014-12-28 19:26:27
阅读次数:
230