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Spring整合Quartz实现动态定时器
一、版本说明 spring3.1以下的版本必须使用quartz1.x系列,3.1以上的版本才支持quartz 2.x,不然会出错。 原因:spring对于quartz的支持实现,org.springframework.scheduling.quartz.CronTriggerBean继承了org.q ...
分类:编程语言   时间:2016-09-07 17:45:02    阅读次数:203
problem 3. Longest Substring Without Repeating Characters
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分类:其他好文   时间:2016-09-06 23:07:41    阅读次数:149
POJ1325(最小顶点覆盖)
Machine Schedule Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 14429 Accepted: 6153 Description As we all know, machine scheduling is a v ...
分类:其他好文   时间:2016-09-04 12:50:01    阅读次数:183
LeetCode 387 First Unique Character in a String
Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1. Examples: Note: You may assume the ...
分类:其他好文   时间:2016-09-03 14:49:53    阅读次数:113
[LeetCode] NO. 387 First Unique Character in a String
[题目] Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1. Examples: Note: You may assum ...
分类:其他好文   时间:2016-09-02 00:22:19    阅读次数:194
LVS的调度算法
LVS的调度算法(Scheduling Method)一共有10种 一、静态方法:仅根据算法本身进行调度 1、rr(Round Robin):轮询 2、wrr(Werghted Round Robin):加权轮询 3、sh(Source Hashing):源地址hash 4、dh(dh):目标地址h ...
分类:编程语言   时间:2016-09-01 18:06:58    阅读次数:165
First Unique Character in a String
Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1. Examples: Note: You may assume the ...
分类:其他好文   时间:2016-08-30 07:03:31    阅读次数:139
Longest Substring Without Repeating Characters
Given a string, find the length of the longest substring without repeating characters. Examples: Given "abcabcbb", the answer is "abc", which the leng ...
分类:其他好文   时间:2016-08-29 06:53:36    阅读次数:139
【LeetCode】3. Longest Substring Without Repeating Characters
题目: Given a string, find the length of the longest substring without repeating characters. Examples: Given "abcabcbb", the answer is "abc", which the ...
分类:其他好文   时间:2016-08-29 01:42:42    阅读次数:141
Leetcode 387 First Unique Character in a String
Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1. Examples: Note: You may assume the ...
分类:其他好文   时间:2016-08-27 14:06:41    阅读次数:156
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