Fence Repair
Time Limit: 2000MS
Memory Limit: 65536K
Total Submissions: 28417
Accepted: 9229
Description
Farmer John wants to repair a small length of the fence aroun...
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其他好文 时间:
2015-02-02 23:17:42
阅读次数:
226
Humidex
Time Limit: 1000MS
Memory Limit: 65536K
Total Submissions: 17719
Accepted: 6420
Description
Adapted from Wikipedia, the free encyclopedia
The humidex is a ...
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其他好文 时间:
2015-02-02 23:17:00
阅读次数:
143
You are climbing a stair case. It takes n steps to reachto the top.
Each time you can either climb 1 or 2 steps. In how many distinct ways canyou climb to the top?
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Dynamic Programming
...
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其他好文 时间:
2015-02-02 23:15:59
阅读次数:
283
Longest Ordered Subsequence
Time Limit: 2000MS
Memory Limit: 65536K
Total Submissions: 35502
Accepted: 15572
Description
A numeric sequence of ai is ordered if a1...
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其他好文 时间:
2015-02-02 23:14:01
阅读次数:
274
if(Input.GetKey(KeyCode.Q)) { transform.Rotate(0,-50*Time.deltaTime,0,Space.Self); } if(Input.GetKey(KeyCode.E)) { transform.Rotate(0,50*Ti...
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编程语言 时间:
2015-02-02 22:44:23
阅读次数:
255
Meteor Shower
Time Limit: 1000MS
Memory Limit: 65536K
Total Submissions: 9677
Accepted: 2718
Description
Bessie hears that an extraordinary meteor shower is comin...
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其他好文 时间:
2015-02-02 21:31:32
阅读次数:
167
#include #include int main(void) { int sum = 0; time_t t,t1; time(&t); //t = time(NULL); std::cout<<ctime(&t); //单...
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其他好文 时间:
2015-02-02 19:52:03
阅读次数:
156
1009. Product of Polynomials (25)时间限制400 ms内存限制65536 kB代码长度限制16000 B判题程序Standard作者CHEN, YueThis time, you are supposed to find A*B where A and B are t...
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其他好文 时间:
2015-02-02 19:36:41
阅读次数:
111
1002. A+B for Polynomials (25)时间限制400 ms内存限制65536 kB代码长度限制16000 B判题程序Standard作者CHEN, YueThis time, you are supposed to find A+B where A and B are two ...
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其他好文 时间:
2015-02-02 19:34:54
阅读次数:
99
java.sql.Date,java.sql.Time和java.sql.Timestamp三个都是java.util.Date的子类(包装类)。 java.sql.Date是java.util.Date的子类,是一个包装了毫秒 值的瘦包装器,允许 JDBC 将毫秒值标识为 SQL DATE 值。毫秒...
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数据库 时间:
2015-02-02 18:20:44
阅读次数:
150