1.首先定义唯一标识：#define GAME_EVENT_PLAYER_EXP_UPDATED "player_exp_updated"2.注册事件监听cocos2d::EventListener* m_pPlayerExpListener;m_pPlayerExpListener = Event...
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其他好文 时间：
2014-08-13 21:57:37
阅读次数：
256
Problem Description
In the game of DotA, Pudge’s meat hook is actually the most horrible thing for most of the heroes. The hook is made up of several consecutive metallic sticks which are of the same...
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其他好文 时间：
2014-08-13 18:59:07
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226
Problem Description
XQ,one of the three Sailormoon girls,is usually playing mobile games on the class.Her favorite mobile game is called “The Princess In The Wall”.Now she give you a problem about th...
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其他好文 时间：
2014-08-13 18:57:07
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224
Gnome TetravexTime Limit:10 Seconds Memory Limit:32768 KBHart is engaged in playing an interesting game, Gnome Tetravex, these days. In the game, at t...
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其他好文 时间：
2014-08-13 18:40:46
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228
Problem Description
FSF is addicted to a stupid tower defense game. The goal of tower defense games is to try to stop enemies from crossing a map by building traps to slow them down and towers which...
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其他好文 时间：
2014-08-13 13:14:47
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196
最开始的时候思路就想错了，就不说错误的思路了。因为这n个数的总和是一定的，所以在取数的时候不是让自己尽可能拿的最多，而是让对方尽量取得最少。记忆化搜索：d(i, j)表示原序列中第i个元素到第j个元素构成的子序列，先手取数能够得到的最大值。sum(i, j) 表示从第i个元素到第j个元素的和因为要让...
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其他好文 时间：
2014-08-13 12:47:56
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247
题目：hdu4944FSF’s game(数论)
题目大意：给定N，然后会有N * （ N + 1）/2个等级的矩形，（1 * 1, 2 * 1, 2* 2, ...N * 1， N * 2.. N* N).将这些矩阵分成大小相同的K * K 的正方形，能够获得金币A * B / gcd（A
/ K， B/ K）；然后给定N，问能够得到的总金币。
解题思路:对于sum（N）：...
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其他好文 时间：
2014-08-13 10:31:50
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262
Problem StatementThe Happy Letter game is played as follows: At the beginning, several players enter the field. Each player has a lowercase English le...
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移动开发 时间：
2014-08-13 03:33:35
阅读次数：
201
Description
In the two-player game "Two Ends", an even number of cards is laid out in a row. On each card, face up, is written a positive integer. Players take turns removing a card from either end...
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其他好文 时间：
2014-08-13 01:18:05
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209
#include
#include
typedef unsigned long long ll;
const ll MOD = (1ULL<<32);
const int N = 500001;
int t, n;
ll ans[N], frc[N];
void init() {
for (ll i = 1; i < N; i++) {
for (ll j = i; j < ...
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其他好文 时间：
2014-08-13 01:14:05
阅读次数：
218
