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racle 11g impdp时 报ORA-12899
racle11gimpdp时报ORA-12899(2012-07-16 16:42:12)转载▼标签:oracleimpimpdpit分类:oracle技术-开发源库ZHS16BGK,汉字在数据库存放的时候占用两个字节目标库UTF8,汉字在数据库里存放的时候占用三个字节由于字符集不同,导致现在数据库...
分类:其他好文   时间:2014-07-19 19:08:26    阅读次数:220
oracle impdp的table_exists_action详解
oracle impdp的table_exists_action详解分类:[oracle]--[备份与恢复]2012-01-06 22:449105人阅读评论(0)收藏举报tableactionoracleschemaobjectimport1 table_exists_action参数说明使用im...
分类:数据库   时间:2014-07-19 19:06:47    阅读次数:381
poj 1094 / zoj 1060 Sorting It All Out
Sorting It All OutTime Limit:1000MSMemory Limit:10000KTotal Submissions:26876Accepted:9271DescriptionAn ascending sorted sequence of distinct values i...
分类:其他好文   时间:2014-07-19 15:03:58    阅读次数:278
[zoj 3774]Power of Fibonacci 数论(二次剩余 拓展欧几里得 等比数列求和)
Power of Fibonacci Time Limit: 5 Seconds      Memory Limit: 65536 KB In mathematics, Fibonacci numbers or Fibonacci series or Fibonacci sequence are the numbers of the following integer sequence...
分类:其他好文   时间:2014-07-19 11:48:45    阅读次数:239
POJ2533 Longest Ordered Subsequence 【最长递增子序列】
Longest Ordered Subsequence Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 32192   Accepted: 14093 Description A numeric sequence of ai is ordered if a1 a...
分类:其他好文   时间:2014-07-19 11:47:53    阅读次数:169
HDU 1003 Max Sum
Problem Description Given a sequence a[1],a[2],a[3]......a[n], your job is to calculate the max sum of a sub-sequence. For example, given (6,-1,5,4,-7), the max sum in this sequence is 6 + (-1) + 5...
分类:其他好文   时间:2014-07-19 08:25:40    阅读次数:224
USACO Section 2.1 Sorting a Three-Valued Sequence
/* ID: lucien23 PROG: sort3 LANG: C++ */ #include #include #include #include using namespace std; void exchange(int nums[], int begin, int end, int N, int x); int sum = 0; int main() { ifstream ...
分类:其他好文   时间:2014-07-19 02:12:25    阅读次数:176
【leetcode刷题笔记】Longest Consecutive Sequence
Given an unsorted array of integers, find the length of the longest consecutive elements sequence.For example,Given[100, 4, 200, 1, 3, 2],The longest ...
分类:其他好文   时间:2014-07-18 18:17:46    阅读次数:290
UVa 11583 Partitioning by Palindromes
?? Description Problem H: Partitioning by Palindromes We say a sequence of characters is a palindrome if it is the same written forwards and backwards. For example, 'racecar' is a palindrome,...
分类:其他好文   时间:2014-07-18 15:13:10    阅读次数:266
[ACM] POJ 2442 Sequence (堆的性质)
解题思路:         有m行,每行n个数,从每行中取出一个数相加一起求出sum,这样的sum有n的m次方个。要求的前n个最小的sum值。 第一次使用STL里面的堆,一开始对pop_heap()有点不太理解,后来明白了,比如对数组heap[n],最大下标为n-1建堆,默认的是建立大顶堆,heap[0]是数组中最大的数,写一条pop_heap()语句,就是把heap[0]和 heap[n...
分类:其他好文   时间:2014-07-18 14:11:34    阅读次数:281
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