///@link http://acm.hdu.edu.cn/showproblem.php?pid=1010///@author Sycamore///@date Aug, 18//fast DFS with pruning#includeusing namespace std;struct co... ...
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其他好文 时间:
2017-08-18 14:36:09
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142
The title of this problem is familiar,isn't it?yeah,if you had took part in the "Rookie Cup" competition,you must have seem this title.If you haven't ...
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其他好文 时间:
2017-08-16 21:43:15
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156
Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s ...
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其他好文 时间:
2017-08-13 11:14:54
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156
Problem Description Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , s ...
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其他好文 时间:
2017-08-10 19:43:58
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138
转载:http://blog.csdn.net/bone_ace/article/details/53107018 前言 “去重”是日常工作中会经常用到的一项技能,在爬虫领域更是常用,并且规模一般都比较大。去重需要考虑两个点:去重的数据量、去重速度。为了保持较快的去重速度,一般选择在内存中进行去重。 ...
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其他好文 时间:
2017-08-08 20:03:03
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162
Bone Collector Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 65099 Accepted Submission(s): 2712 ...
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其他好文 时间:
2017-08-08 13:55:52
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129
题目链接:点击打开链接 题目描写叙述:给定一个迷宫,给一个起点和一个终点。问是否能恰好经过T步到达终点?每一个格子不能反复走 解题思路:dfs+剪枝 剪枝1:奇偶剪枝,推断终点和起点的距离与T的奇偶性是否一致,假设不一致,直接剪掉 剪枝2:假设从当前到终点的至少须要的步数nt加上已经走过的步数ct大 ...
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其他好文 时间:
2017-08-04 16:13:38
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124
上一篇翻译了图集解析单元,今天把骨架解析也翻译完了(二进制,.skel文件)。1000多行代码,把我累的。。。 spine.core.bone, spine.core.slot, spine.core.skin, spine.core.attachment, spine.core.constrain ...
题目描述: The doggie found a bone in an ancient maze, which fascinated him a lot. However, when he picked it up, the maze began to shake, and the doggie c ...
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其他好文 时间:
2017-07-26 22:04:00
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211
根据常识,有: 但根据骨骼动画的定义,又有: 对比两式,可得bindpose的定义: 即骨骼bone的bindpose是:在绑定时刻,将mesh上的顶点由mesh的局部空间变换到bone的局部空间的变换。 参考:https://tieba.baidu.com/p/4360653128 ...
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其他好文 时间:
2017-07-25 15:50:38
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275