码迷,mamicode.com
首页 >  
搜索关键字:farmer john wants th    ( 8242个结果
Checkio: Roman numerals
题目: Roman numerals come from the ancient Roman numbering system. They are based on specific letters of the alphabet which are combined to signify the sum (or, in some cases, the difference) of th...
分类:其他好文   时间:2014-06-20 12:27:09    阅读次数:394
Android多线程研究(6)——多线程之间数据隔离
在上一篇《Android多线程研究(5)——线程之间共享数据》中对线程之间的数据共享进行了学习和研究,这一篇我们来看看如何解决多个线程之间的数据隔离问题,什么是数据隔离呢?比如说我们现在开启了两个线程,这两个线程都要同时给同一个全局变量data赋值,各个线程操作它赋值后的变量数据,这里就需要用到隔离。先看一段代码:import java.util.Random; public class Th...
分类:移动开发   时间:2014-06-20 11:25:58    阅读次数:321
TCP_NODELAY详解
在网络拥塞控制领域,我们知道有一个非常有名的算法叫做Nagle算法(Nagle algorithm),这是使用它的发明人John Nagle的名字来命名的,John Nagle在1984年首次用这个算法来尝试解决福特汽车公司的网络拥塞问题(RFC 896),该问题的具体描述是:如果我们的应用程序一次...
分类:其他好文   时间:2014-06-11 08:57:34    阅读次数:267
leetcode--Convert Sorted List to Binary Search Tree
Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST.public class Solution { /** Convert th...
分类:其他好文   时间:2014-06-10 00:22:44    阅读次数:259
cocos2d-x3.0-结合TH脚本引擎
cocos2d-x3.0-结合TH脚本引擎...
分类:其他好文   时间:2014-06-08 16:57:51    阅读次数:202
POJ 3615 Cow Hurdles.
Description Farmer John wants the cows to prepare for the county jumping competition, so Bessie and the gang are practicing jumping over hurdles. They are getting tired, though, so they want to be ...
分类:其他好文   时间:2014-06-08 15:55:10    阅读次数:199
POJ 3278 Catch That Cow
Catch That Cow Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 44070   Accepted: 13764 Description Farmer John has been informed of the location of a fugitiv...
分类:其他好文   时间:2014-06-08 15:44:43    阅读次数:238
Usaco Open09 Gold
Problem 1: Ski Lessons [Brian Jacokes, 2002]Farmer John wants to take Bessie skiing in Colorado. Sadly, Bessieis not really a very good skier.Bessie h...
分类:其他好文   时间:2014-06-08 01:30:57    阅读次数:406
USACO JAN 2012 Bronze
Problem 1: Gifts [Kalki Seksaria and Brian Dean, 2012]Farmer John wants to give gifts to his N (1 2 #include 3 #include 4 #include 5 #include 6 ...
分类:其他好文   时间:2014-06-08 00:46:18    阅读次数:613
projecteuler---->problem=18----Maximum path sum I
By starting at the top of the triangle below and moving to adjacent numbers on the row below, the maximum total from top to bottom is 23. 3 7 4 2 4 6 8 5 9 3 That is, 3 + 7 + 4 + 9 = 23. Find th...
分类:其他好文   时间:2014-06-07 13:45:25    阅读次数:189
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!