这题是黄巨大出的比赛题.http://poj.org/problem?id=3278DescriptionFarmer John has been informed of the location of a fugitive cow and wants to catch her immediatel...
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其他好文 时间:
2014-06-19 00:58:53
阅读次数:
510
BACKGROUNDProcessor power consumption has become a major issue in recent years. The current trend of processor design to multi-core architecture as ea...
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其他好文 时间:
2014-06-18 22:16:54
阅读次数:
435
Struts Problem ReportStruts has detected an unhandled exception:Messages:No suitable driver found for jdbc:mysql://localhost:3306/hibernate_basicCanno...
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数据库 时间:
2014-06-18 18:41:57
阅读次数:
249
大家都知道在IIS中有个HTTP keep-alive设置,很多人可能和我们一样,以为这样设置后,IIS会就在发送响应内容时加上这个http header——Connection: keep-alive。今天在偶然的情况下突然发现——不是这样的,这是一个让人瞠目结舌的骗局——只要用的是http 1....
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其他好文 时间:
2014-06-18 14:21:17
阅读次数:
308
Nightmare
时间限制:1000 ms | 内存限制:65535 KB
难度:4
描述
Ignatius had a nightmare last night. He found himself in a labyrinth with a time bomb on him. The labyrinth has an exit, Ignatius should ...
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Web程序 时间:
2014-06-16 18:57:52
阅读次数:
268
Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:
Integers in each row are sorted from left to right.The first integer of each...
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其他好文 时间:
2014-06-15 14:12:44
阅读次数:
238
Problem Description
In a factory, there are N workers to finish two types of tasks (A and B). Each type has N tasks. Each task of type A needs xi time to finish, and each task of type B needs yj ti...
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其他好文 时间:
2014-06-15 11:26:42
阅读次数:
195
原始题目如下,意为寻找数组和最大的子串,返回这个最大和即可。
Find the contiguous subarray within an array (containing at least one number) which has the largest sum.
For example, given the array [?2,1,?3,4,?1,2,1,?5,4],
the...
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其他好文 时间:
2014-06-14 15:08:00
阅读次数:
224
曾经整理过一篇《关于PHP连接处理中set_time_limit()、connection_status()和ignore_user_abort()深入解析》,是讲解浏览器客户端断开时,服务器PHP脚本的处理。
这篇文章,将讲解一下服务器PHP脚本怎样主动断开与浏览器的连接,主要方法是使用http协议header中的Content-Length和Connection
Content-Length的作用:浏览器接收到指定Content-Length大小的消息实体后,则会断开与服务器的连接。
Connectio...
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Web程序 时间:
2014-06-14 09:24:21
阅读次数:
229
之前我有看过别人写的文章,说到如何获取客户端IP地址,代码如下:var io = require("socket.io").listen(server);io.sockets.on("connection", function (socket) { var address = sock...
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其他好文 时间:
2014-06-14 08:48:28
阅读次数:
412