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[leetcode][easy][Array][561][Array Partition I]
Array Partition I 题目 "链接" 题目描述 给定大小为 2n 的整型数组,你的任务是将这些整数分为 组,即 (a1,b1), (a2, b2),...,(an, bn),使得所有的 min(ai,bi) 之和最大,其中i的值为从1到n。 输出上述要求中的 和 。 约定 1. 是一个 ...
分类:其他好文   时间:2018-12-18 11:01:18    阅读次数:148
24. Swap Nodes in Pairs - Medium
Given a linked list, swap every two adjacent nodes and return its head. Example: Note: Your algorithm should use only constant extra space. You may no ...
分类:其他好文   时间:2018-12-15 11:48:51    阅读次数:117
Leetcode-954 Array of Doubled Pairs(二倍数对数组)
真-瞎j8写写就过了 ...
分类:编程语言   时间:2018-12-09 14:13:05    阅读次数:289
22. Generate Parentheses - Medium
Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: M ...
分类:其他好文   时间:2018-12-07 12:58:12    阅读次数:210
LeetCode 606. Construct String from Binary Tree
You need to construct a string consists of parenthesis and integers from a binary tree with the preorder traversing way. The null node needs to be rep ...
分类:其他好文   时间:2018-12-05 23:20:14    阅读次数:303
LeetCode 561. Array Partition I
Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), …, (an, bn) which makes sum of mi ...
分类:其他好文   时间:2018-12-05 22:56:03    阅读次数:184
bbmerge的结果记录
Adapters counted: 144143Total time: 1548.035 seconds. Pairs: 50367942Joined: 9636485 19.132%Ambiguous: 40723752 80.853%No Solution: 7705 0.015%Too Sho ...
分类:其他好文   时间:2018-12-05 00:19:16    阅读次数:267
UVA10405 Longest Common Subsequence【LCS+DP】
Given two sequences of characters, print the length of the longest common subsequence of both sequences.     Sequence 1:  &nb ...
分类:其他好文   时间:2018-12-02 19:20:57    阅读次数:225
AWS Add Key Pair to Elastic Beanstalk Instance 给EB实例加密钥
Go to Elastic Beanstalk -> Configuration -> Security -> Virtual machine permissions -> EC2 key pair. Choose your key pair. If you do not have one, The ...
分类:其他好文   时间:2018-12-01 15:05:09    阅读次数:186
493. Reverse Pairs(BST, BIT, MergeSort)
Given an array nums, we call (i, j) an important reverse pair if i < j and nums[i] > 2*nums[j]. You need to return the number of important reverse pai ...
分类:其他好文   时间:2018-12-01 00:09:56    阅读次数:235
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