问题:将数字转化为罗马数字分析:将所有的数字打表出来class Solution {public: string intToRoman(int num) { char c[10][10][10]={{"0","I","II","III","IV","V","VI","VII","...
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其他好文 时间:
2014-08-01 10:32:21
阅读次数:
215
题目: Given n, generate all structurally unique BST's (binary search trees) that store values 1...n.For example,Given n = 3, your program should return....
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编程语言 时间:
2014-08-01 04:53:31
阅读次数:
279
选择Nios II Library选择location,这样的话库文件时独立的,而如果选择 Make library depend on a BSP的话会依赖BSP,如果BSP被删除了那新工程编译时会报错。添加c源文件和h头文件然后build project然后新建工程:file->Nios II ...
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移动开发 时间:
2014-07-31 16:17:47
阅读次数:
342
思路:统计每位出现的次数,mod3;对于k同样适用 1 class Solution { 2 public: 3 int singleNumber(int A[], int n) { 4 int a[32] = {0}; 5 int i = 0; 6 ...
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其他好文 时间:
2014-07-31 13:14:46
阅读次数:
140
Warning (15714): Some pins have incomplete I/O assignments. Refer to the I/O Assignment Warnings report for details解释:后续高级的芯片的 drive strength 和 slew r...
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其他好文 时间:
2014-07-31 12:22:26
阅读次数:
320
1.The Nios II processor’s JTAG debug module provides a single, consistent method to connect to the processor using a JTAG download cable.2.Altera BSPs...
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移动开发 时间:
2014-07-31 09:41:55
阅读次数:
285
题目:Given a collection of integers that might contain duplicates, S, return all possible subsets.Note:Elements in a subset must be in non-descending o....
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编程语言 时间:
2014-07-31 09:38:05
阅读次数:
341
Just corner case..class Solution {public: ListNode *reverseBetween(ListNode *head, int m, int n) { if(m == n) return head; ListNode *...
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其他好文 时间:
2014-07-31 09:34:05
阅读次数:
245
题目:Given a set of distinct integers, S, return all possible subsets.Note:Elements in a subset must be in non-descending order.The solution set must n....
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编程语言 时间:
2014-07-31 05:22:45
阅读次数:
286
The only difference with version I is: one number can only be used once:class Solution {public: vector > ret; struct Rec { Rec() : sum...
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其他好文 时间:
2014-07-31 05:22:25
阅读次数:
239