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Path Sum II leetcode java
题目:Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals the given sum.For example:Given the below binary tree and ....
分类:编程语言   时间:2014-07-31 05:22:15    阅读次数:287
A + B Problem II(杭电1002)
/*A + B Problem II Problem Description I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.   Input The first line of the input contains an...
分类:其他好文   时间:2014-07-30 17:38:54    阅读次数:306
大数A+B 【杭电-1002】 附题
/* A + B Problem II Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 209912    Accepted Submission(s): 40404 Problem Description I have a...
分类:其他好文   时间:2014-07-30 17:32:24    阅读次数:226
Linked List Cycle II
题目描述:Given a linked list, return the node where the cycle begins. If there is no cycle, returnnull.Follow up:Can you solve it without using extra spac...
分类:其他好文   时间:2014-07-30 17:18:44    阅读次数:204
Best Time to Buy and Sell Stock II leetcode java
题目:Say you have an array for which the ith element is the price of a given stock on day i.Design an algorithm to find the maximum profit. You may com....
分类:编程语言   时间:2014-07-30 05:35:03    阅读次数:309
Word Break II leetcode java
题目:Given a string s and a dictionary of words dict, add spaces in s to construct a sentence where each word is a valid dictionary word.Return all suc....
分类:编程语言   时间:2014-07-30 03:19:32    阅读次数:341
HDU 2830 Matrix Swapping II
给一个矩阵,依然是求满足条件的最大子矩阵不过题目中说任意两列可以交换,这是对题目的简化求出h数组以后直接排序,然后找出(col-j)*h[j]的最大值即可(这里的j是从0开始)因为排序会影响到h数组下一行的求解,所以将h数组中的元素复制到temp数组中去,再排序 1 //#define LOCAL ...
分类:移动开发   时间:2014-07-30 00:40:22    阅读次数:232
[LeetCode]Binary Tree Level Order Traversal II
[LeetCode]Binary Tree Level Order Traversal II...
分类:其他好文   时间:2014-07-29 14:42:48    阅读次数:145
HDU 2830 Matrix Swapping II (最大完全子矩阵之可移动列)
HDU 2830 Matrix Swapping II (最大完全子矩阵之可移动列)...
分类:移动开发   时间:2014-07-29 14:36:08    阅读次数:236
【leetcode】Pascal's Triangle II (python)
其实每一行的结果是二项式展开的系数,但是考虑到当给定的参数过大的时候,在求组合的过程中会出现溢出(中间过程要用到乘法),但是这样的算法的时间复杂度是O(N),所以在参数不太大的时候,还是不错的。 这里用迭代的方法来求,当然复杂度就高了,是O(N^2),这里主要说下迭代时候的技巧,即在一个列表(数组)里进行迭代,实现如此的操作,要求在求下一行的时候,要从后往前进行,若是从前向后,就把后面要用的变量...
分类:编程语言   时间:2014-07-29 14:35:28    阅读次数:452
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