Count the Buildings
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 738 Accepted Submission(s): 246
Problem Description
There are N ...
分类：
其他好文 时间：
2015-04-16 21:59:00
阅读次数：
220
From :http://cesiumjs.org/2013/04/25/Horizon-culling/在虚拟地球(如, Cesium)的开发过程中， 我们需要能够快速确定场景中的对象, 如地形瓦片(terrain tiles), 卫星(satellites), 建筑物(buildings), 交...
分类：
其他好文 时间：
2015-04-16 19:47:33
阅读次数：
322
Problem Description
Have you ever heard the story of Blue.Mary, the great civil engineer? Unlike Mr. Wolowitz, Dr. Blue.Mary has accomplished many great projects, one of which is the Guanghua Building.
The public opinion is that Guanghua Building is no...
分类：
编程语言 时间：
2015-03-05 22:24:55
阅读次数：
265
DescriptionFarmer John has taken his cows on a trip to the city! As the sun sets, the cows gaze at the city horizon and observe the beautiful silhouettes formed by the rectangular buildings.The entire...
分类：
其他好文 时间：
2015-02-25 17:09:45
阅读次数：
210
模式的诞生与定义模式起源于建筑业而非软件业模式(Pattern)之父——美国加利佛尼亚大学环境结构中心研究所所长Christopher Alexander博士《A Pattern Language: Towns, Buildings, Construction》——253个建筑和城市规划模式模式Co...
分类：
其他好文 时间：
2015-01-08 19:29:56
阅读次数：
273
Urban ElevationsAn elevation of a collection of buildings is an orthogonal projection of the buildings onto a vertical plane. An external elevation of...
分类：
其他好文 时间：
2014-11-20 20:20:20
阅读次数：
272
Building Fire Stations
Time Limit: 5 Seconds
Memory Limit: 131072 KB Special Judge
Marjar University is a beautiful and peaceful place. There are N buildings and
N - 1 bidirection...
分类：
其他好文 时间：
2014-10-24 20:45:46
阅读次数：
258
Building Fire Stations
Time Limit: 5 Seconds Memory Limit: 131072 KB Special Judge
Marjar University is a beautiful and peaceful place. There are N buildings and N - 1 bidirectional ro...
分类：
其他好文 时间：
2014-10-13 12:21:25
阅读次数：
123
Count the Buildings
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 528 Accepted Submission(s): 171
Problem Description
There ar...
分类：
其他好文 时间：
2014-08-25 22:53:35
阅读次数：
309
HDU 4372 Count the Buildings（组合数学-斯特林数,组合数学-排列组合）
题目大意：
n个高度为1~n的房子排成一排，从前面看可以看到f个房子，从后面看可以看到b个房子，问你有多少种安排方法？
解题思路：
最高的房子为中间，左边有f-1个房子可以看到，右边有b-1个房子，也就是总共选出f+b-2个房子，剩余的房子在它的左边或右边，可以理解为分成了f+b-2组，且含有这个指定的顺序，看成第一类斯特林数，再从f+b-2组里面选出f-1组，答案就是：c[f+b-2][f-1]*s(n...
分类：
其他好文 时间：
2014-08-25 21:15:22
阅读次数：
350
