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[poj] The Wedding Juicer | [lintcode] Trapping Rain Water II
问题描述给定一个二维矩阵,每个元素都有一个正整数值,表示高度。这样构成了一个二维的、有高度的物体。请问该矩阵可以盛放多少水?相关题目:POJ The Wedding JuicerDescriptionFarmer John’s cows have taken a side job designing interesting punch-bowl designs. The designs are cr...
分类:移动开发   时间:2015-08-09 12:34:24    阅读次数:143
Trapping Rain Water
问题描述Givennnon-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after rainin...
分类:移动开发   时间:2015-07-31 10:20:20    阅读次数:133
LeetCode42:Trapping Rain Water
Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For example,  Given [0,1,0,2,1,0,1,3,2,1,2,1]...
分类:移动开发   时间:2015-07-20 19:45:52    阅读次数:175
Twitter算法面试题详解(Java实现)——Trapping Rain Water
【算法题:求出高低不同的砖中能存多少水】「Trapping Rain Water」Givennnon-negative integers representing an elevation map where the width of each bar is 1, compute how much ...
分类:移动开发   时间:2015-07-16 19:14:33    阅读次数:120
[LeetCode] Trapping Rain Water
Note: The following idea is in fact from the last answer inthis link, which leads to a clean code. I just reorganize it and add some explanations. I h...
分类:移动开发   时间:2015-07-15 01:07:55    阅读次数:197
[LeetCode][Java] Trapping Rain Water
题意: Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For example,  Given [0,1,0,2,1,0,1,3...
分类:移动开发   时间:2015-07-13 18:40:16    阅读次数:119
leetCode 42.Trapping Rain Water(凹槽的雨水) 解题思路和方法
Trapping Rain Water Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For example,  Given [0...
分类:移动开发   时间:2015-07-11 15:10:33    阅读次数:164
42 Trapping Rain Water
42 Trapping Rain Water链接:https://leetcode.com/problems/trapping-rain-water/ 问题描述: Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water...
分类:移动开发   时间:2015-07-11 09:09:39    阅读次数:152
[leedcode 42] Trapping Rain Water
Givennnon-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining.Fo...
分类:移动开发   时间:2015-07-10 20:28:55    阅读次数:141
042 Trapping Rain Water
这道题有一个直观的想法, 就是分别记录每个点的左侧和右侧最大值 对于height[i] 这一点能装的水等于 min(leftMax[i], rightMax[i]) - height[i]. 这个解法需要扫描2次序列。以下的方法只需要扫描一次序列即可。class Solution: # @pa...
分类:移动开发   时间:2015-07-09 06:13:42    阅读次数:124
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