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UVa11030-Predator II
Problem D Predator II Time limit: 2 seconds   Oh No!!! The predator has entered the room again. But this time it is a different kind of room. The room is a square of size 1000...
分类:其他好文   时间:2014-07-22 23:03:13    阅读次数:358
android开源项目之OTTO事件总线(二)官方demo解说
官方demo见 https://github.com/square/otto注意自己该编译版本为2.3以上,默认的1.6不支持match_parent属性,导致布局文件出错。另外需要手动添加android-support-v4和otto到自己的libs文件夹。主要代码逻辑:1,在主页面点clear按...
分类:移动开发   时间:2014-05-16 19:19:36    阅读次数:334
【LeetCode】Spiral Matrix II
Given an integern, generate a square matrix filled with elements from 1 ton2in spiral order.For example,Givenn=3,You should return the following matri...
分类:其他好文   时间:2014-05-12 19:53:23    阅读次数:332
POJ 2002 点的hash
Squares Time Limit: 3500MS   Memory Limit: 65536K Total Submissions: 15489   Accepted: 5864 Description A square is a 4-sided polygon whose sides have equal length and adja...
分类:其他好文   时间:2014-05-11 20:56:36    阅读次数:416
CSU 1424 Qz’s Maximum All One Square
原题链接:http://acm.csu.edu.cn/OnlineJudge/problem.php?id=1424 逐渐找到做这种题的感觉了。 二分法。g[i][j]存储坐标(i, j)的值,s[i][j]存储的值为左上角为起始点(1,1),右下角为(i, j)的矩形区域内所有值的和,那么...
分类:其他好文   时间:2014-05-10 22:55:11    阅读次数:347
Sum square difference
简单:e sum of the squares of the first ten natural numbers is,12 + 22 + ... + 102 = 385The square of the sum of the first ten natural numbers is,(1 + 2 ...
分类:其他好文   时间:2014-05-07 20:23:43    阅读次数:338
POJ3254:Corn Fields(状态压缩)
Description Farmer John has purchased a lush new rectangular pasture composed of M by N (1 ≤ M ≤ 12; 1 ≤ N ≤ 12) square parcels. He wants to grow some yummy corn for the cows on a number of square...
分类:其他好文   时间:2014-05-07 05:46:43    阅读次数:323
POJ 2676 数码问题DLX
Sudoku Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 13023   Accepted: 6455   Special Judge Description Sudoku is a very simple task. A square table with 9...
分类:其他好文   时间:2014-05-03 00:31:30    阅读次数:400
Codeforces 1
A. Theatre Square:         题目地址:http://codeforces.com/contest/1/problem/A         题目大意:n*m的长方形用a*a的正方形覆盖,允许超出长方形,问需要几个正方形。         算法讨论:计算长和宽分别需要几个a,相乘即可。         Code: #include #include using...
分类:其他好文   时间:2014-04-30 22:15:39    阅读次数:272
HDU 1398 Square Coins (母函数-整数拆分变形)
Square Coins Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 7612    Accepted Submission(s): 5156 Problem Description People in Sil...
分类:其他好文   时间:2014-04-29 13:38:21    阅读次数:316
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