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HDU4911:Inversion
Problem Description bobo has a sequence a1,a2,…,an. He is allowed to swap two adjacent numbers for no more than k times. Find the minimum number of inversions after his swaps. Note: The numbe...
分类:其他好文   时间:2014-08-06 14:51:38    阅读次数:177
[ACM] POJ 2479 Maximum sum (动态规划求不相交的两段子段和的最大值)
Maximum sum Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 33363   Accepted: 10330 Description Given a set of n integers: A={a1, a2,..., an}, we define a...
分类:其他好文   时间:2014-08-06 11:59:41    阅读次数:186
[ACM] POJ 2593 Max Sequence (动态规划,最大字段和)
Max Sequence Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 15569   Accepted: 6538 Description Give you N integers a1, a2 ... aN (|ai| You should ou...
分类:其他好文   时间:2014-08-06 11:59:11    阅读次数:232
中国剩余定理
中国剩余定理用于求解 x≡ai(mod mi),其中mi两两互质,x有唯一解。 令M为mi的乘积,wi = M/mi,wi关于模mi的逆元为pi,即满足wi*pi + mi*qi = 1. 则上述方程组等价于 x≡ w1*p1*a1 + w2*p2*a2 +......+wk*pk*ak(mod M)..................................................
分类:其他好文   时间:2014-08-05 22:45:40    阅读次数:191
HDU - 4911 Inversion
Problem Description bobo has a sequence a1,a2,…,an. He is allowed to swap two adjacent numbers for no more than k times. Find the minimum number of inversions after his swaps. Note: The number...
分类:其他好文   时间:2014-08-05 22:44:03    阅读次数:248
Leetcode | Container With Most Water
Given n non-negative integers a1, a2, ..., an, where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpo...
分类:其他好文   时间:2014-08-05 18:54:19    阅读次数:282
POJ 3468 A Simple Problem with Integers(线段树 区间更新)
Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of operation is to add some given number to each number in a given interval. The other ...
分类:其他好文   时间:2014-08-05 11:15:59    阅读次数:243
poj 3399 Product(模拟)
# include # include # include using namespace std; int cmp(int x,int y) { return x>y; } int main() { int a[110],a1[110],a2[110],ans[110]; int n,k,k1,k2,i,k3; while(~scanf("%d%d",&n,&k)) { k1...
分类:其他好文   时间:2014-08-04 21:46:48    阅读次数:237
UVA 12232 - Exclusive-OR(带权并查集)
UVA 12232 - Exclusive-OR 题目链接 题意:有n个数字,一开始值都不知道,每次给定一个操作,I a v表示确认a值为v,I a b v,表示确认a^b = v,Q k a1 a2 a3 ... ak,表示判断这些数字的异或值能否确定,能确定就输出值,如果有矛盾就停止 思路:带权并查集,权表示和父结点的异或值,那么多数判断的时候,只要所有数字和他的父结点的异或...
分类:其他好文   时间:2014-08-04 14:24:57    阅读次数:208
【HackerRank】Sherlock and MiniMax
题目连接:Sherlock and MiniMaxWatson gives Sherlock an arrayA1,A2...AN.He asks him to find an integerMbetweenPandQ(both inclusive), such that,min {|Ai-M|, ...
分类:其他好文   时间:2014-08-03 23:04:06    阅读次数:380
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